Going after these block gives you the risk of getting stuck behind them, consuming all your balls in the process. High-numbered blocks will require more balls to break, balls that you may not even have on your snake just yet. While it is true that breaking these blocks will result in a higher score overall, there is also a good chance it will result in the end of your run. Prioritize Low-Numbered BlocksĪ lot of players make the mistake of going after high-numbered blocks. Just make sure you have enough balls on your snake or your run will end. You get points even if you don’t break the block completely. Every time you hit a block, it adds to your score. Doing so will expend a ball but will also reduce the counter on the block. The main point is to use those balls to ram head-first into the blocks. Head For The BlocksĬollecting balls to make your snake longer is only a part of Snake VS Block. The more balls you have, the longer your run will be so don’t ignore any of them. The numbers indicate the number of balls that will be added to your snake. Prioritize the balls with higher numbers on them. These balls will be crucial in determining how long you will survive in Snake VS Block. Try to get all of them as much as you can. There are balls scattered throughout the game for you to pick up. Make sure you check out our Snake VS Block tips and tricks for some help on getting the highest scores! 1. The mechanics may be simple but the gameplay get more and more complicated the longer your snake gets. You can pick up additional balls to make the snake longer, and keep going as far as you can. In this arcade title, you get to control a snake made up of balls, with the goal of breaking as many blocks as you can. Nodes.position = new Vector2(-2.90f, ) Īlso, unless you somehow increment the two LerpTime variables, you're misusing the Lerp function, and you don't need it in this context either.Snake VS Block is an addictive new mobile game for Android and iOS devices. Nodes.Translate(Vector3.up * ltaTime * 4) Nodes.Translate(Vector3.right * ltaTime * horizontalInput * 10) Vector3 pos = _ įloat horizontalInput = Input.GetAxis("Horizontal") It should look like this: public void Move() When you moved all the nodes, move the node 0 according to the user input.Then for each i node, assign it the position of the i-1 node.Assing this node the position of the (n-1)-th node.If I understand what you want to do, you should approach this in the reverse order. However I still can't obtain the smooth snake movement like in the real games. Instead of having the snake move upwards, the snake stays in the same position and the blocks move downwards. UPDATE: I changed the basic logic for the snake movement in my game. Nodes.position = Vector2.Lerp(Nodes.position, newPos, ltaTime * 10) Nodes.position = Vector2.Lerp(Nodes.position, newPos, ltaTime * 14) Nodes.GetComponent().velocity = new Vector2(curPos.x -, 0) * 20 If (Input.GetMouseButton(0) & () = false & Nodes.Count > 0)ĬurPos = (curPos) I'm wondering if anyone has a solution to this. This is my current code which does work as a snake movement but does not follow the exact path of the next node. What's special about the snake movement in the game is that the previous node follows the next ones path perfectly, both in X and in Y. Most of the physics are pretty straight forward but I cannot seem to re-create the snake movement. I am trying to re-create the popular SnakeVSBlock mobile game.
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